Answer:
d = 84 m
Explanation:
As we know that when an object moves with uniform acceleration or deceleration then we can use equation of kinematics to find the distance moved by the object
here we know that
initial speed [tex]v_i = 42 m/s[/tex]
final speed [tex]v_f = 0[/tex]
time taken by the car to stop
[tex]t = 4s[/tex]
now the distance moved by the car before it stop is given as
[tex]d = \frac{v_f + v_i}{2} \times t [/tex]
now we have
[tex]d = \frac{42 + 0}{2} \times 4[/tex]
[tex]d = 84 m[/tex]
The car that travels to the right with a speed of 42 m/s, skids 84 meters for 4 seconds before it comes to a stop.
The distance traveled by car before coming to a stop can be calculated with the following equation:
[tex] v_{f}^{2} = v_{i}^{2} + 2ad [/tex] (1)
Where:
[tex] v_{f}[/tex]: is the final speed = 0 (it stops)
[tex] v_{i}[/tex]: is the initial speed = 42 m/s
a: is the acceleration
d: is the distance =?
We need to find the acceleration. We can use the next equation:
[tex] v_{f} = v_{i} + at [/tex] (2)
Where:
t: is the time = 4.0 s
Hence, the acceleration is:
[tex]a = \frac{v_{f} - v_{i}}{t} = \frac{0 - 42 m/s}{4.0 s} = -10.5 m/s^{2}[/tex]
Now, the car skid the following meters before coming to a stop (eq 1).
[tex]d = \frac{v_{f}^{2} - v_{i}^{2}}{2a} = \frac{-(42 m/s)^{2}}{2(-10.5 m/s^{2})} = 84 m[/tex]
Therefore, the car skids 84 meters before coming to a stop.
To find more about stopping distance, go here: https://brainly.com/question/4299689?referrer=searchResults
I hope it helps you!
