Respuesta :

AndyBryer

Answer:

(3a-1)(3a+1)

Step-by-step explanation:

We can quickly see with this problem that it is the difference of two squares as 9a^2 is (3a)^2 and 1 is 1^2 and therefore can factorise quickly using this rule.

x^2-y^2 = (x-y)(x+y) where x = 3a and y = 1

kudzordzifrancis

ANSWER

[tex]{(3 {a})^{2} } - {1}^{2} = (3a + 1)(3a - 1)[/tex]

EXPLANATION

We want to simplify completely:

[tex]9 {a}^{2} - 1[/tex]

We express the two terms as difference of two squares;

[tex] {(3 {a})^{2} } - {1}^{2} [/tex]

Recall and apply the following identity;

[tex]{x}^{2} - {y}^{2} = (x + y)(x - y)[/tex]

We apply this identity to obtain:

[tex]{(3 {a})^{2} } - {1}^{2} = (3a + 1)(3a - 1)[/tex]

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