Answer:
(-3,2)
Step-by-step explanation:
When the point P(x,y) is reflected in the line [tex]x=k[/tex], the mapping is
[tex]P(x,y)\to P'(2k-x,y)[/tex].
The image of (1,2) after a reflection about x = 6 is
[tex](1,2)\to (2\times6-1,2)[/tex].
[tex](1,2)\to (12-1,2)[/tex].
[tex](1,2)\to (11,2)[/tex].
When the resulting point is again reflected in the line x=4, we obtain
[tex](11,2)\to (2\times4-11,2)[/tex].
[tex](11,2)\to (8-11,2)[/tex].
[tex](11,2)\to (-3,2)[/tex].
Therefore the image of (1,2) after a
reflection about x = 6 followed by a
reflection about x = 4 is (-3,2)
