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A 13.7 N force is applied to a cord wrapped around a disk of radius 0.43 m. The disk accelerates uniformly from rest to an angular speed of 30.3 rad/s in 3.43 s. Determine the angular acceleration of the disk. Hint: the average acceleration is the change in angular speed over time.

Respuesta :

Answer:

8.83 rad/s²

Explanation:

w₀ = initial angular speed of the disk = 0 rad/s

w = final angular speed of the disk = 30.3 rad/s

t = time period of rotation of the disk = 3.43 sec

[tex]\alpha[/tex] = Angular acceleration of the disk

Angular acceleration of the disk is given as

[tex]\alpha = \frac{w-w_{o}}{t}[/tex]

inserting the values

[tex]\alpha[/tex] = (30.3 - 0)/3.43

[tex]\alpha[/tex] = 8.83 rad/s²

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