Answer:
0.00191 meter is the diameter of the sphere.
Explanation:
Velocity of the rigid sphere = [tex]v=\frac{1m}{500 s}[/tex]
Density of the fluid = [tex]\rho _f=1000 kg/m^3[/tex]
Density of the particle= [tex]\rho _p=1100 kg/m^3[/tex]
Viscosity of the fluid =[tex]\eta =100 centiPoise = 1 Poise=0.1 Kg/(m s)[/tex]
Radius of the sphere = r
[tex]v=\frac{2}{9}\times \frac{\rho _p-\rho _f}{\eta }gr^2[/tex]
(Terminal velocity)
[tex]\frac{1 m}{500 s}=\frac{2}{9}\times \frac{1100 kg/m^3-1000 kg/m^3}{0.1 kg/(m s)}\times 9.8 m/s^2\times r^2[/tex]
r = 0.00191 m
0.00191 meter is the diameter of the sphere.
