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The graph shows the solution to a system of inequalities:

Which of the following inequalities is modeled by the graph?

A.
[tex]4x + 3y \leqslant 12;x \geqslant 0[/tex]
B.
[tex]4x + 3y \geqslant 12;x \geqslant 0[/tex]
C.
[tex]4x - 3y \leqslant 12;x \geqslant 0[/tex]
D.
[tex] - 4x - 3y \leqslant 12;x \geqslant 0[/tex]

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The graph shows the solution to a system of inequalitiesWhich of the following inequalities is modeled by the graphAtex4x 3y leqslant 12x geqslant 0texBtex4x 3y class=

Respuesta :

calculista

Answer:

Option A. [tex]4x+3y\leq 12[/tex] and [tex]x\geq 0[/tex]

Step-by-step explanation:

we know that

The solution of the first inequality is the shaded area below the solid line [tex]4x+3y=12[/tex]

The solid line passes through the points (0,4) and (3,0) (the y and x intercepts)

therefore

The first inequality is

[tex]4x+3y\leq 12[/tex]

The solution of the second inequality is the shaded area to the right of the solid line x=0

therefore

The second inequality is

[tex]x\geq 0[/tex]

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