contestada

24. Suppose a clay model of a koala bear has a mass of 0.200 kg and slides on ice at a speed of 0.750 m/s. It runs into another clay model, which is initially motionless and has a mass of 0.350 kg. Both being soft clay, they naturally stick together. What is their final velocity?

Respuesta :

MathPhys

Answer:

0.273 m/s

Explanation:

Momentum is conserved:

mu = (m + M) v

(0.200 kg) (0.750 m/s) = (0.200 kg + 0.350 kg) v

v = 0.273 m/s

The momentum of the conservation said that the momentum before collision is equal to the momentum before collision.The final velocity will be 0.273 m/sec.

What is law of conservation of momentum?

The momentum of the conservation said that the momentum before collision is equal to the momentum before collision.

The given data in the problem is;

m is the mass of clay model before collision= 0.200 Kg

u is the sliding velocity before collision=0.75 m/sec

M is the mass after collision= 0.350 Kg

v is the velocity after collision=?

On applying the law of conservation of momentum we get;

[tex]\rm mu = (m + M) v \\\\\ (0.200 kg) (0.750 m/s) = (0.200 kg + 0.350 kg) v \\\\ v = 0.273 m/s[/tex]

To learn more about the law of conservation of momentum refer ;

https://brainly.com/question/1113396

Otras preguntas