Answer:
0.545 m
Explanation:
K. E = 26 MeV = 26 x 1.6 x 10^-13 J = 4.16 x 10^-12 J
B = 1.35 T
Let r be the radius of curvature
The formula for the kinetic energy of a cyclotron is given by
[tex]K.E. = \frac{B^{2}q^{2}r^{2}}{2m}[/tex]
m = 1.67 x 10^-27 kg, q = 1.6 x 10^-19 c
[tex]4.16\times 10^{-12} = \frac{1.35^{2}\times (1.6\times 10^{-19})^{2}r^{2}}{2\times 1.67\times 10^{-27}}[/tex]
r = 0.545 m
