Answer:
-99.1 V
Explanation:
For a free electron accelerated from rest, the final kinetic energy of the electron is equal to the change in electric potential energy of the electron:
[tex]K=\Delta U\\\frac{1}{2}mv^2 = q\Delta V[/tex]
where
[tex]m=9.11\cdot 10^{-31}kg[/tex] is the mass of the electron
[tex]v=5.9\cdot 10^6 m/s[/tex] is the final speed
[tex]q=-1.6\cdot 10^{-19} C[/tex] is the charge of the electron
[tex]\Delta V[/tex] is the potential difference
Solving for [tex]\Delta V[/tex], we find
[tex]\Delta V=\frac{mv^2}{2q}=\frac{(9.11\cdot 10^{-31})(5.9\cdot 10^6)^2}{2(-1.6\cdot 10^{-19})}=-99.1 V[/tex]
