Answer:
The radius is: [tex]2\sqrt{3}[/tex]
Step-by-step explanation:
The equation of a circle in center-radius form is:
[tex](x - h)^2 + (y - k)^2 = r^2[/tex]
Where the center is at the point (h, k) and the radius is "r".
So, given the equation of the circle:
[tex]x^2+y^2=12[/tex]
You can identify that:
[tex]r^2=12[/tex]
Then, solving for "r", you get that the radius of this circle is:
[tex]r=\sqrt{12}\\\\r=2\sqrt{3}[/tex]
