Explanation:
Charge of electron in He, [tex]q_e=1.6\times 10^{-19}\ kg[/tex]
Charge of proton in He, [tex]q_p=1.6\times 10^{-19}\ kg[/tex]
Distance between them, [tex]d=2.7\times 10^{-10}\ m[/tex]
We need to find the electric force between them. It is given by :
[tex]F=k\dfrac{q_eq_p}{d^2}[/tex]
[tex]F=-9\times 10^9\times \dfrac{(1.6\times 10^{-19}\ C)^2}{(2.7\times 10^{-10}\ m)^2}[/tex]
[tex]F=-3.16\times 10^{-9}\ N[/tex]
Since, there are two protons so, the force become double i.e.
[tex]F=2\times 3.16\times 10^{-9}\ N[/tex]
[tex]F=6.32\times 10^{-9}\ N[/tex]
So, the correct option is (c). Hence, this is the required solution.
