Answer:
H(3) = 288 feet
H(4) = 320 feet
H(5) = 320 feet
H(6) = 288 feet
Step-by-step explanation:
A ball is shot out of a cannon at ground level so the ball will follow a parabolic path.
Since height H and time t of the ball have been described by a function H(t) = 144t - 16t²
Then we have to find the values of H(3), H(4), H(5) and H(6).
H(3) = 144×3 - 16(3)²
= 432 - 144
= 288 feet
H(4) = 144×4 - 16(4)²
= 576 - 256
= 320 feet
H(5) = 144×5 - 16(5)²
= 720 - 400
= 320 feet
H(6) = 144×6 - 16(6)²
= 864 - 576
= 288 feet
Here we are getting the value like H(3), H(6) and H(4), H(5) are same because in a parabolic path ball first increase in the height above the ground then after the maximum height it decreases.
Therefore, after t = 3 and t = 6 heights of the canon ball are same. Similarly after t = 4 and t = 5 heights of the canon above the ground are same.