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A person with mass of 68kg rides in an elevator that has an upward acceleration of 1.5 m/s2. Draw 1 body diagram of the person and determine the magnitude of the force of the elevator floor ree on the person?

Respuesta :

Answer:

N = 768.4 N

Explanation:

As per given FBD we can see that the person inside the elevator have two forces on it

1) Normal force upwards

2) weight downwards

Now from Newton's law of motion we can say

[tex]F_{net} = ma[/tex]

[tex]N - mg = ma[/tex]

[tex]N = mg + ma[/tex]

now plug in all values in it

[tex]N = 68(1.5) + 68(9.8)[/tex]

[tex]N = 768.4 N[/tex]

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