At some instant and location, the electric field associated with an electromagnetic wave in vacuum has the strength 98.5 V/m. Find the magnetic field strength, the energy density, and the power flow per unit area, all at the same instant and location.

Respuesta :

Answer:

[tex]B = 3.28 \times 10^{-7} T[/tex]

[tex]u_{density} = 4.3 \times 10^{-8} J/m^3[/tex]

[tex]Intensity = 12.88 W/m^2[/tex]

Explanation:

As we know that the electric field strength in vacuum due to electromagnetic waves is given as

[tex]E = 98.5 V/m[/tex]

now we know the relation between electric field and magnetic field as

[tex]B = \frac{E}{c}[/tex]

[tex]B = \frac{98.5}{3\times 10^8}[/tex]

[tex]B = 3.28 \times 10^{-7} T[/tex]

For energy density we know that

[tex]u_{density} = \frac{1}{2}\epsilon_0 E^2[/tex]

[tex]u_{density} = \frac{1}{2}(8.85 \times 10^{-12})(98.5)^2[/tex]

[tex]u_{density} = 4.3 \times 10^{-8} J/m^3[/tex]

Power flow per unit area is given as

[tex]Intensity = energy density \times speed[/tex]

[tex]Intensity = (4.3 \times 10^{-8})(3\times 10^8)[/tex]

[tex]Intensity = 12.88 W/m^2[/tex]