Consider a very long, straight wire of uniform positive charge density. In the space below, describe the electric field of the wire. In particular, what direction does it point? Does its strength depend on position? If so, how? Note any symmetries of interest.

Respuesta :

The wire is very long, which in the world of high school physics we treat as infinitely long. We would use Gauss' law to derive an equation giving the electric field strength at some point away from the wire:

E = λ/(2πε₀r)

E = electric field strength, λ = linear charge density, r = distance from wire

We can see from this equation that the field strength is dependent on the distance from the wire; the field strength is proportional to the inverse of r.

We should also note the very special symmetry of the electric field around the wire: The field points radially outward from the center of the wire.

The electric field strength depends; on the position of the wire and it's direction is radially outward from the center of wire.

What is the electric field strength?

We are told the wire is very long, straight wire and of uniform positive charge density.

Thus, from Gauss' law the electric field at any point within the wire is;

E = λ/(2πε₀r)

Where;

E = electric field strength

λ = linear charge density

r = distance from wire

ε₀ is permittivity of free space

From the equation above, we see that the electric field strength is inversely proportional to the distance and as such is dependent on the distance from the wire

Finally, the direction in which the electric field of the wire points will be radially outward from the center of the wire.

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