Respuesta :
Answer:
The amount of work is 89600 ft-lb.
Explanation:
Given that,
Length of the cable = 160 ft
Weight density = 7 lb/ft
Weight of cable to be filled = 7(160-x)
We need to calculate the amount of work
Using formula of work done
[tex]\int{dW}=\int_{0}^{160}{7(160-x)}dx[/tex]
On integration
[tex]W=[1120x-\dfrac{7x^2}{2}]_{0}^{160}[/tex]
[tex]W=1120\times160-0-\dfrac{7\times(160)^2}{2}+0[/tex]
[tex]W=89600\ ft-lb[/tex]
Hence, The amount of work is 89600 ft-lb.
Answer:
The amount of work is 89600 ft-lb.
Explanation:
Given that:
Length of the cable = 160 ft
Weight density = 7 lb/ft
Weight of cable to be filled = 7(160-y)
We need to calculate the amount of work
Using formula of work done:
[tex]W = \int\limits^a_b {7*(160-y)} \, dy \\\\W = {7*(160y-y^2/2)}\\a = 160\\b = 0\\\\W = 7*(160^2-160^2/2)\\W = 89,600ft-lb[/tex]
Hence, The amount of work is 89,600 ft-lb.
