calculate the molarity of each of the following solutions:
(a) 293 gram HCL in 666 ml of solution, a concentrated HCL solution
(b)2.026 g in 0.1250 ml of a solution used as an unknown in general Chemistry laboratory
(c) 0.001 mg Cd2+ in 0.100 L the maximum permissible concentration of cadmium in drinking water
(d) 0.0079 g C7H5SNO3 in one ounce(29.6mL), concentration of saccharin in a diet soft drink

Respuesta :

Answer:

Explanation:

Molarity  is the number of moles or grammes of a substance present in one dm³ of a solution. Molarity is often expressed in the unit of moldm⁻³.

Molarity  = [tex]\frac{concentration}{Molar mass of substance}[/tex]

Molarity = [tex]\frac{number of moles }{Volume}[/tex]

(a) 293 gram HCL in 666 ml of solution, a concentrated HCL solution

We are given:

Mass of HCl = 293g

Volume of solution = 666ml

Unknown:

Molarity of HCl

Let us convert the volume into dm³:

             1000mL = 1dm³

               666mL = [tex]\frac{666}{1000}[/tex] dm³ , 0.666dm³

Now, we solve for molarity:

Molarity = [tex]\frac{number of moles }{volume}[/tex]

The number of moles is unknown and can be derieved from the equation below:

Number of moles of HCl = [tex]\frac{mass}{molar mass}[/tex]

Molar mass of HCl = 1 + 35.5 = 36.5gmol⁻¹

Number of moles of HCl =  [tex]\frac{293}{36.5}[/tex] = 8.03mole

Now we proceed to find molarity:

Molarity = [tex]\frac{8.03}{0.666}[/tex] = 12.06moldm⁻³

(b)2.026 g in 0.1250 ml of a solution used as an unknown in general Chemistry laboratory:

Given parameters:

Mass of solute = 2.062g

Volume of solution = 0.1250mL

Unkown:

Molarity of the solution

Since molarity simply expresses the amount of solute in a substance, we can also use the express below:

Molarity = [tex]\frac{mass of solute}{Volume of solution}[/tex] = [tex]\frac{2.062}{0.125}[/tex] = 16.496g/mL

(c) 0.001 mg Cd2+ in 0.100 L the maximum permissible concentration of cadmium in drinking water

Given parameters:

mass of cadmium ions = 0.001mg

Volume of solution = 0.1L

Unknown:

Molarity of the solution =?

Molarity = [tex]\frac{mass of solute}{volume of solution}[/tex] =  [tex]\frac{0.001}{0.1}[/tex] = 0.01mg/L

(d) 0.0079 g C7H5SNO3 in one ounce(29.6mL), concentration of saccharin in a diet soft drink:

Given parameters:

Mass of saccharin, C₇H₅SNO₃  = 0.0079g

Volume of solution = 29.6mL

Unknown:

Molarity = ?

Molarity = [tex]\frac{mass of solute}{volume of solution}[/tex] = [tex]\frac{0.0079}{29.6}[/tex] = 0.00027g/mL