Respuesta :
Answer:
20 % from the next generation will be male XiY
Step-by-step explanation:
females have are XX always and males are XY, so when cross a woman an a man the probability of have a male is 50 %
XX - XY
⇒XX
⇒XY
⇒XX
⇒XY
P (female) = [tex]\frac{2}{4} =\frac{1}{2}[/tex] = 0.5 = 50 %
P (male) = [tex]\frac{2}{4} =\frac{1}{2}[/tex] = 0.5 = 50 %
Then the probability oh have a male XiY is dependent first oh have a male and second that the male will be XiY
The probability of a dependent probability is the product of the probabilities
P (XiY) = P (male) * P (male wit the character Xi)
P (male wit the character Xi) = P (of be XiY from the amount of males from the cross XiXi with XsY) * P (XiXi) + P (of be XiY from the amount of males from the cross XiXs with XsY) * P (XiXs) + P (of be XiY from the amount of males from the cross XsXs with XsY) * P (XsXs)
1. XiXi - XsY
⇒ XiXs (female)
⇒XiXs (female)
⇒XiY (male)
⇒XiY (male)
From the 2 male, both can be XiY
P (of be XiY from the amount of males from the cross XiXi with XsY) = [tex]\frac{2}{2} =1[/tex]
2. XiXs - XsY
⇒ XiXs (female)
⇒XsXs (female)
⇒XiY (male)
⇒XsY (male)
From the 2 male, one can be XiY
P (of be XiY from the amount of males from the cross XiXs with XsY) = [tex]\frac{1}{2} [/tex]
3. XsXs - XsY
⇒ XsXs (female)
⇒XsXs (female)
⇒XsY (male)
⇒XsY (male)
From the 2 male,any of them can be XiY
P (of be XiY from the amount of males from the cross XsXs with XsY) = [tex]\frac{0}{2} =0[/tex]
P (male wit the character Xi) = P (of be XiY from the amount of males from the cross XiXi with XsY) * P (XiXi) + P (of be XiY from the amount of males from the cross XiXs with XsY) * P (XiXs) + P (of be XiY from the amount of males from the cross XsXs with XsY) * P (XsXs)
P (of be XiY from the amount of males from the cross XiXi with XsY) = 1
P (of be XiY from the amount of males from the cross XiXs with XsY) = [tex]\frac{1}{2}[/tex]
P (of be XiY from the amount of males from the cross XsXs with XsY) = 0
P (male wit the character Xi) = [tex]1*\frac{15}{100} +\frac{1}{2} *\frac{50}{100} +0 * \frac{35}{100} [/tex]= [tex]\frac{40}{100}=\frac{2}{5}[/tex]
P (XiY) = P (male) * P (male wit the character Xi)
P(XiY) = [tex]\frac{1}{2} *\frac{2}{5} =\frac{1}{5} = 0.2[/tex]
20 % from the next generation will be male XiY
