Respuesta :
Answer:
Linear speed, v = 23.86 miles per hour
Explanation:
It is given that,
Angular speed of gondola, [tex]\omega=14\ rev/min=1.46\ rad/sec[/tex]
The gondola is 24 feet from the ride's center, r = 24 feet = 7.31 m
We need to find the linear speed of the gondola. It can be calculated using the following relation as :
[tex]v=r\times \omega[/tex]
[tex]v=7.31\ m\times 1.46\ rad/s[/tex]
v = 10.67 m/s
or
v = 23.86 miles per hour
So, the linear speed of the gondola is 23.86 miles per hour. Hence, this is the required solution.
Answer:
The linear speed of the gondola is 23.99 mils/hr.
Explanation:
Given that,
Number = 14 revolution /m
Distance = 24 feet
We need to calculate the linear speed of the gondola in miles per hour
Using formula of speed
[tex]v = r\omega[/tex]
[tex]v=\dfrac{r2\pi N}{60}[/tex]
Put the value into the formula
[tex]v=\dfrac{24\times2\times\pi\times14}{60}[/tex]
[tex]v=35.18\ ft/s[/tex]
[tex]v=23.99\ mile/hr[/tex]
Hence, The linear speed of the gondola is 23.99 mils/hr.
