Answer:
1660 V
Explanation:
Resistance should be determined and then voltage drop across the power line can be determined.
R = ρ L /A
Here ρ = Resistivity of aluminum = [tex]2.7\times 10^{-8}\Omega m[/tex]
L = length = 32 km = 32,000 m
Area of cross section = A = π r² = π (0.027/2)² = 0.00057255 m²
Resistance = R =
([tex]2.7\times 10^{-8}\Omega m[/tex] (32,000)/(0.00057255) = 1.5090 Ohms.
Voltage drop = V = I R = (1100)(1.5090) = 1659.9 V.
(If resistivity value is different, then the resistance will be different and hence final answer for voltage will also vary ).
