Answer:
θ=66.42°
Explanation:
Given that
F= 100 lb
The force along a-a is 40 lb
Lets take θ is the angle made by force F from a-a
So the component of force F along a-a will F cosθ and the component of force along b-b is F sinθ.
The force along a-a given that 40 lb,so we can say that
F cosθ= 40
100 cosθ = 40
cosθ= 0.4
θ=66.42°
The angle from a-a is 66.42°.
