Answer:
V = 10.03 m/s
Explanation:
It is given that,
Velocity of the river, v₁ = 2.33 m/s
Velocity of the boat, v₂ = 9.76 m/s
Width of the river, d = 212 m
Let v is the velocity of the boat relative to the shore. It can be calculated using vector sum as :
[tex]v=\sqrt{v_1^2+v_2^2}[/tex]
[tex]v=\sqrt{2.33^2+9.76^2}[/tex]
v = 10.03 m/s
So, the velocity of the boat relative to shore is 10.03 m/s. Hence, this is the required solution.