Two tiny metal spheres A and B, mass mA = 5.00 g and mB = 10.0 g, have equal positive charge q = 5.00 μC. The spheres are connected by a massless nonconducting string of length d = 1.00 m, which is much greater than the radii of the spheres.
a. What is the electric potential energy of the system?

Respuesta :

AMB000

Answer:

U=0.22475 Joules

Explanation:

The electric potential energy between 2 charges can be calculated with the formula [tex]U=k\frac{q_1q_2}{r}[/tex], where (in S.I.):

[tex]k=8.99\times10^{9} Nm^{2}C^{-2}[/tex] is the Coulomb constant

[tex]q_1=q_2=5.00\times10^{-6}C[/tex] are the values of the charges

[tex]r=1.00m[/tex] their separation

So we have [tex]U=k\frac{q_1q_2}{r}=0.22475J[/tex]