Answer:
Required energy = 4758 J
Explanation:
Specific heat capacity of a material is the amount of energy required to raise the temperature of one kilogram (kg) of that material through one degree Celsius (°C).
Given data :
Specific heat capacity = c = 2440 J/kg.°C
Mass = m = 150 g = 0.15 kg
Initial temperature = 22°C
Final temperature = 35°C
Change in Temperature = ΔT = 13°C
Energy = E = ?
Using the following formula and substituting the values, we get:
E = m × c × ΔT
E = 0.15 × 2440 × 13
E = 4758 J