Answer: The mass of sulfuric acid present in 60 mL of solution is 34.1 grams
Explanation:
We are given:
44 % (m/m) solution of sulfuric acid. This means that 44 grams of sulfuric acid is present in 100 grams of solution.
To calculate volume of a substance, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of solution = 1.343 g/mL
Mass of solution = 100 g
Putting values in above equation, we get:
[tex]1.343g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.343g/mL}=77.46mL[/tex]
To calculate the mass of sulfuric acid present in 60 mL of solution, we use unitary method:
In 77.46 mL of solution, mass of sulfuric acid present is 44 g
So, in 60 mL of solution, mass of sulfuric acid present will be = [tex]\frac{44g}{77.46mL}\times 60mL=34.1g[/tex]
Hence, the mass of sulfuric acid present in 60 mL of solution is 34.1 grams
