Answer:
[tex]y-4=(x-11)[/tex] or [tex]y=(x-11)+4[/tex]
Step-by-step explanation:
We know that the slope of the line is 1, so we can write it in terms of any two points belonging to the line, as per the difinition of slope:
[tex]slope=\frac{y_1-y_0}{x_1-x_0} \\1=\frac{y_1-y_0}{x_1-x_0}[/tex]
We can use instead of [tex](x_1,y_1)[/tex] any general point (x,y) on the line, and for [tex](x_0,y_0)[/tex] the point we are interested in: (11,4)
That way the slope can be written as:
[tex]1=\frac{y-4}{x-11}[/tex]
Next we can solve for y if this format is the one your instructor prefers:
[tex]1=\frac{y-4}{x-11}\\1(x-11)=(y-4)\\(x-11)+4 =y[/tex]
