Answer:
hey
Step-by-step explanation:
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Answer: The required slope of line C'D' is [tex]-\dfrac{3}{7}.[/tex]
Step-by-step explanation: Given that the points (-5, 8) and D (2, 5) lie on line CD. And, the points C' and D' are created by translating points C and D left 6 units.
We are to find the slope of line C'D'.
We know that
if a point (x, y) is translated 6 units left, then its new co-ordinates becomes
(x, y) ⇒ (x-6, y).
So, after translating 6 units left, the co-ordinates of points C(-5, 8) and D(2, 5) becomes
C(-5, 8) ⇒ C'(-5-6, 8) = (-11, 8),
D(2, 5) ⇒ D'(2-6, 5) = (-4, 5).
We know that the slope of a line having points (a, b) and (c, d) on it is given by
[tex]m=\dfrac{d-b}{c-a}.[/tex]
Therefore, the slope of line C'D' is
[tex]m=\dfrac{5-8}{-4-(-11)}=\dfrac{-3}{-4+11}=-\dfrac{3}{7}.[/tex]
Thus, the required slope of line C'D' is [tex]-\dfrac{3}{7}.[/tex]
