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A centrifugal pump is required to pump water to an open water link situated 4 km away from the location of the pump through a pipe of diameter 0.2 m having Darcy's friction factor of 0.01. The average speed of water in the pipe is 2 m/s. If it maintains a constant head of 5 m in the tank, what is the corresponding pressure in bar abs.

Respuesta :

Answer:

P= 5.5 bar

Explanation:

Given that

L= 4000 m

d= 0.2 m

Friction factor(F) = 0.01

speed V= 2 m/s

Head = 5 m

Head loss due to friction

[tex]h_f=\dfrac{FLV^2}{2gd}[/tex]

[tex]h_f=\dfrac{0.01\times 4000\times 2^2}{2\times 9.81\times 0.2}[/tex]

[tex]h_f=40.77m[/tex]

So the total head(H) = 5 + 40.77 + 10.3 =56.07

Where 10.3 m is the atmospheric head.

We know that

P=ρ g H

So total Pressure

P= 1000 x 9.81 x 56.07 Pa

[tex]P=5.5\times 10^5\ Pa[/tex]

P= 5.5 bar

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