Answer:
(a) 1.215 x 10^-13 J
(b) n = 7.6 x 10^5
Explanation:
distance, r = 8.3 x 10^-10 m
Force, F = 192.9 x 10^-9 N
Let the charge is q.
(a) According to the Coulomb's law
[tex]F=\frac{Kq\times q}{r^{2}}[/tex]
[tex]192.9\times10^{-9}=\frac{9\times10^{9}\times q\times q}{\left (8.3\times 10^{-10} \right )^{2}}[/tex]
q = 1.215 x 10^-13 C
(b) Let n number of electrons are missing.
[tex]n = \frac{q}{e}=\frac{1.215\times10^{-13}}{1.6\times10^{-19}}[/tex]
n = 7.6 x 10^5
