Respuesta :
Answer:
a) -2.038 m/s²
b) 40.33 mph
c) 312.5 m
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
[tex]v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-25^2}{2\times 150}\\\Rightarrow a=-2.083\ m/s^2[/tex]
Acceleration of the boat is -2.083 m/s² if the boat will stop at 150 m.
[tex]v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -1\times 150+25^2}\\\Rightarrow v=18.03\ m/s[/tex]
Speed of the boat by when it will hit the dock is 18.03 m/s
Converting to mph
[tex]1\ mile=1609.34\ m[/tex]
[tex]1\ h=3600\ seconds[/tex]
[tex]18.03\times \frac{3600}{1609.34}=40.33\ mph[/tex]
Speed of the boat by when it will hit the dock is 40.33 mph
[tex]v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-25^2}{2\times -1}\\\Rightarrow s=312.5\ m[/tex]
The distance at which the boat will have to start decelerating is 312.5 m
