Answer:
D. 520 N
Explanation:
According to the impulse theorem, the change in momentum of the ball is equal to the impulse exerted on the ball, mathematically:
[tex]\Delta p = I = F \Delta t[/tex]
where
[tex]\Delta p[/tex] is th change in momentum
F is the average force exerted on the ball
[tex]\Delta t[/tex] is the time of contact
The change in momentum of the ball is
[tex]\Delta p = m(v-u)[/tex]
where
m = 57 g = 0.057 kg is the mass of the ball
u = 45 m/s is the initial velocity
v = -33 m/s is the final velocity (in the opposite direction)
Substituting,
[tex]\Delta p = (0.057)(-33-45)=4.45 kg m/s[/tex]
The time of the collision is
[tex]\Delta t = 0.0085 s[/tex]
Therefore, the average force is
[tex]F=\frac{\Delta p}{\Delta t}=\frac{-4.45}{0.0085}=-523 N[/tex]
So, the magnitude is approximately 520 N.
