69angel69
contestada

A steel ball rolls with constant velocity on a tabletop 0.950 m high. It rolls off and hits the ground 0.352 m from the edge of the table
C) What is the final velocity of the object in the vertical direction?

Respuesta :

Answer:

4.3 m/s

Explanation:

In order to find the final velocity of the ball, we can just analyze its vertical motion.

In fact, the ball is in free fall along the vertical direction: this means that it has a constant acceleration, so we can use the following suvat equation

[tex]v^2-u^2=2as[/tex]

where

v is the final vertical velocity

u is the initial vertical velocity

a is the acceleration

s is the displacement

In this problem, we know:

u = 0 (the ball starts from rest)

[tex]a=g=9.8 m/s^2[/tex] is the acceleration of gravity (taking downward as positive direction)

s = 0.950 m (the height of the tabletop)

Solving for v,

[tex]v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(0.950)}=4.3 m/s[/tex]