Answer: 0.99
Step-by-step explanation:
As per given , we have
[tex]H_0: \mu=4\\\\H_1: \mu<4[/tex] , since the alternative hypothesis is left-tailed , so the test is a left-tailed test.
The test statistic was computed to be 2.998.
Also, the variance was unknown, so we use t-test.
For n= 8 , degree of freedom : df= n-1=7
P-value for left -tail test with df=7 and test statistic value t=2.998 : 0.99000069 ≈ 0.99 [Using online p-value calculator]
Hence, the required p-value : 0.99
