Answer:
[tex]P_{pump}= 68600Pa[/tex]
Explanation:
We understand that the sum of the pressures in the tank and the pump is equal to that of the Nozzle,
In this way,
[tex]P_{tank} + P_{pump} = P_{nozzle}[/tex]
For the pressure we also know that it is given by
[tex]P=\rho gh[/tex]
[tex]\rho gh_1 + P_{pump} = \rho gh_2[/tex]
So,
[tex]P_{pump} = \rho g(h2 - h1)[/tex]
[tex]P_{pump}= 1000*9.8(27-20)[/tex]
[tex]P_{pump}= 68600Pa[/tex]