Answer:
1.63 x 10^-7 second
Explanation:
charge, q = 2 e = 2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C
mass, m = 6.64 x 10^-27 kg
Magnetic field, B = 0.80 T
radius, r = 0.30 m
Time period , T = ?
[tex]T = \frac{2\pi m}{Bq}[/tex]
By substituting the values
[tex]T = \frac{2\times 3.14\times 6.64\times 10^{-27}}{0.8\times 3.2 \times 10^{-19}}[/tex]
T = 1.63 x 10^-7 second
Thus, the time to take one circular round is 1.63 x 10^-7 second.
