Answer:
(a) [tex]0.408\ Am^{2}[/tex]
(b) 0.03142 Nm
Solution:
As per the question:
Current, I = 6.8 A
Magnetic field, B = 77 mT = 0.077 T
Now,
Area of the loop, A = [tex]\frac{1}{2}\times base\times height[/tex]
A = [tex]\frac{1}{2}\times 0.3\times 0.4 = 0.06\ m^{2}[/tex]
(a) To calculate the magnetic dipole moment in the loop:
[tex]\mu = I\times A[/tex]
where
[tex]\mu[/tex] = Magnetic dipole moment
[tex]\mu = 6.8\times 0.06 = 0.408\ Am^{2}[/tex]
Now,
(b) To calculate the torque in the loop:
[tex]\tau = \mu B = 0.408\times 0.077 = 0.03142\ Nm[/tex]
