Answer:
(a) 2.51 m/s
(b) 0.011
Explanation:
mass of person, M = 72.3 kg
initial velocity of person, U = 2.99 m/s
mass of sled, m = 13.9 kg
initial velocity of sled, U = 0
(a) Let the velocity of person and the sled is V
By using the conservation of momentum
M x U + m x u = (M + m) x V
72.3 x 2.99 + 13.9 x 0 = (72.3 + 13.9) V
216.177 = 86.2 V
V = 2.51 m/s
(b) initial velocity , V = 2.51 m/ s
Final velocity, V' = 0
distance, s = 30 m
Let μ be the coefficient of friction.
Use third equation of motion
[tex]V'^{2}=V^{2}+2as[/tex]
0 = 2.51 x 2.51 - 2 x μ x 9.8 x 30
μ = 0.011
