a truck can be rented from company A for $120 a day plus $0.40 per mile. Company B charges $70 a day plus $0.50 per mile to rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same
So how you go about this problem is to first write an equation for how much each company will cost. For Company A, it costs $120 plus some more. The some more part can just be written as .4x where x is the number of miles (2 miles = .4+.4 = .4(2) =.8) So for if the cost for Company A is "A" [tex]A=120+.4x[/tex]
Do the same thing for Company B but with the different numbers [tex]B=70+.5x[/tex]
Find the number of miles in a day at which the rental costs for Company A and Company B are the same "The same" here means equal so set the two equations equal to each other (that means the cost of Company A=the cost of Company B or A=B)
[tex]A=B[/tex] [tex]120+.4x=70+.5x[/tex]
Now use algebra to solve for x [tex]120+.4x=70+.5x[/tex] [tex]50+.4x=.5x[/tex] [tex]50=.1x[/tex] [tex] \frac{50}{.1} = \frac{.1x}{.1} [/tex] [tex]500=x[/tex]
