The value of [tex]2 \times(7 \times 1)[/tex] is -80
Given that x y is a real number
Also given that [tex]x \times y = x(x - y)[/tex]
We are asked to find the value of [tex]2 \times (7 \times 1)[/tex]
To solve it we have to first solve terms in brackets.
[tex]\begin{array}{l}{\text {So, } 7 \times 1=7(7-1) \quad[\text {from given rule }]} \\\\ {\rightarrow 7 \times 1=7 \times 6} \\\\ {\rightarrow 7 \times 1=42} \\\\ {\text {Now, the required expression is modified as } 2 \times 42} \\\\ {\text {Then, } 2 \times 42=2(2-42)=2(-40)=-80} \\\\ {\text {Hence, the value of } 2 \times(7 \times 1)=-80}\end{array}[/tex]