Hey there! :)
Equation 1) -2x + y = 14
Equation 2) 4x - 6y = 4
Add 2x to both sides of equation 1 so that we can get the value of y.
y = 2x + 14
Now, plug the value of y into our second equation.
4x - 6(2x + 14) = 4
Simplify.
4x - 12x - 84 = 4
Add 84 to both sides.
4x - 12x = 4 + 84
Simplify.
-8x = 88
Divide both sides by -8.
x = -11
Now, plug our value of x into our first equation in order to find y.
-2x + y = 14
-2(-11) + y = 14
22 + y = 14
y = -8
Therefore, the systems of equation variables are : (-11, -8)
~Hope this helped! :)
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For solving such questions we need to know the linear inequations .
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Liner inequations can be solved with many methods . But here as mentioned we have to solve with substitution method .
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Substitution method is the method of finding the value of one variable from equation 1 and then substituting the value in the equation 2 .
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-2x + y = 14 --- ( i )
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4x - 6y = 4
2 ( 2x - 3y ) = 4
2x - 3y = 4 / 2
2x - 3y = 2 --- ( ii )
As given , -2x + y = 14
➠ y = 14 + 2x
Now, we will substitute the value of y in eq ( ii )
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➠ 2x - 3y = 2
➠ 2x - 3 ( 14 + 2x ) = 2
➠ 2x - 42 - 6x = 2
➠ 2x - 6x = 2 + 42
➠ -4x = 44
➠ x = 44 / - 4
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➠ x = -11
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[tex]\sf{\underline{\boxed{\huge{\blue{\mathbb{x = - 11 }}}}}}[/tex]
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➠ -2x + y = 14
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➠ - 2 × - 11 + y = 14
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➠ 22 + y = 14
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➠ y = 14 - 22
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➠ y = - 8
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[tex]\sf{\underline{\boxed{\huge{\blue{\mathbb{y = -8}}}}}}[/tex]
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