What value of the equilibrium constant, K, at 25ºC corresponds to a large negative value of ΔGº?


Small negative value
Small positive value
Large negative value
Large positive value

Respuesta :

znk

Answer:

Large negative value  

Explanation:

ΔG° = -RTlnK

[tex]\ln K = -\dfrac{\Delta G^{\circ}}{RT}[/tex]

If K is large, lnK is large, and ΔG° is large and negative.