Answer:
option C
Explanation:
Let mass of the bullet be m and velocity be v
mass of gun be M and bullet be V
now,
using conservation of momentum for gun 1
(M+m) V' = 2 mv + 3 MV
V' = 0
3 M V = - 2 mv
momentum of gun 1 =- 2 mv---------(1)
now for gun 2
(M+m) V' = mv + MV
V' = 0
M V = - mv
momentum of gun 1 = -mv-----------(2)
dividing equation (1) by (2)
[tex]\dfrac{P_m1}{P_m2} = \dfrac{- 2mv}{-mv}[/tex]
[tex]\dfrac{P_m1}{P_m2} = \dfrac{2}{1}[/tex]
the correct answer is option C