Answer:
The slope of the given line 1 is -4/5.
The slope of the given line 2 is 0.
The line 2 has a greater slope then line 1.
Step-by-step explanation:
The slope of a line with points (x1,y1) and (x2,y2) is given as:
[tex]m = \frac{y_2- y_1}{x_2-x_1}[/tex]
Now, Here the, points of the line 1 are A (-2,7) and B (3,3)
So, here, the slope of line AB is [tex]m = \frac{3 -7}{3-(-2)} = \frac{-4}{3 +2} = \frac{-4}{5}[/tex]
Hence, the slope of the given line 1 is -4/5.
Now, Here the, points of the line 2 are P (5,1) and Q (9,1)
So, here, the slope of line PQ is [tex]m = \frac{1-1}{9-5} = \frac{0}{4} = 0[/tex]
Hence, the slope of the given line 2 is 0.
Now, as we can see 0 > ( -4 / 5)
So, the line 2 has a greater slope then line 1.
