So, the required probabilities are,
Part(a):P(A)=0.6
Part(b):P(B)=0.1
Given that:
There are five Oklahoma state officials,
Governor (G), Lieutenant Governor (L), Secretary of State (S), Attorney General (A), and Treasurer (T).
All possible samples of size 3 are obtained from the population of five officials.
Here order does not matter so we use the combinations.
[tex]5_C_3=10[/tex] possible samples.
So, S={GLS,GLA,GLT,GSA,GST,GAT,LSA,LST,LAT,SAT}
Hence, n(s)=10
Part(a):
Let A denotes the event that the governor is included in the sample.
A={GLS,GLA,GLT,GSA,GST,GAT}
That is n(A)=6
So, the probability that the governor is included in the sample,
[tex]P(A)=\frac{n(A)}{n(S)} \\=\frac{6}{10}\\ =0.6[/tex]
Part(b):
Let B denotes the event that the government attorney general and the treasure are included in the sample.
B={GAT}
That is n(B)=1
Hence, the probability that the government attorney general and the treasure are included in the sample is,
[tex]P(B)=\frac{n(B)}{n(S)} \\=\frac{1}{10} \\=0.1[/tex]
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