Answer:
Null hypothesis: p= 0.65
Alternative Hypothesis: p < 0.65
Explanation:
Below are the null and alternative hypothesis,
Null hypothesis: p= 0.65
Alternative Hypothesis: p < 0.65
Test statistic for text of significance
z = (pcap –p)/ [tex]\sqrt{ [p*(1-p)/n]}[/tex]
z = (0.576 – 0.65)/ [tex]\sqrt{[0.65×1-0.65)/125]}[/tex]
z = 1.73
P- value Approach
p-value = 0.0414
As P-value < 0.05, we reject the null hypothesis
There is sufficient evidence to conclude that the mother consumed vitamin D supplements during pregnancy. A researcher in a northern region felt that the percentage should be lower for this region because with reduced hours of sunshine during winter months, pregnant women tended to use of higher doses of supplements to compensate.