Two blocks (m1 = 40 kg, m2 = 30 kg) are connected by a compressed spring, and are initially at rest. The spring breaks and the two objects fly apart from one another. If the speed of the first block is 15 m/s, what is the speed of the second block?

Respuesta :

Answer:

Speed of second block will be 20 m /sec in opposite direction

Explanation:

We have given the mass of two blocks [tex]m_1=40kg[/tex] and [tex]m_2=30kg[/tex]

As both the blocks are initially at rest so [tex]u_1=0m/sec\ and\ u_2=0m/sec[/tex]

Speed of first block [tex]v_1=15m/sec[/tex]

We have to find the speed of second block, that is [tex]v_2[/tex]

From momentum conservation we know that

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

[tex]40\times 0+30\times 0=40\times 15+30\times v_2[/tex]

[tex]v_2=-20m/sec[/tex]

So speed of second block will be 20 m /sec in opposite direction.