To solve this problem it is necessary to use the concepts related to pressure depending on the depth (or height) in which the object is on that fluid. By definition this expression is given as
[tex]P = P_{atm} +\rho gh[/tex]
Where,
[tex]P_{atm} =[/tex] Atmospheric Pressure
[tex]\rho =[/tex]Density, water at this case
g = Gravity
h = Height
The equation basically tells us that under a reference pressure, which is terrestrial, as one of the three variables (gravity, density or height) increases the pressure exerted on the body. In this case density and gravity are constant variables. The only variable that changes in the frame of reference is the height.
Our values are given as
[tex]P_{atm} = 1.013*10^5Pa[/tex]
[tex]\rho = 1000Kg/m^3[/tex]
[tex]g = 9.8m/s^2[/tex]
[tex]h = 0.78m[/tex]
Replacing at the equation we have,
[tex]P = P_{atm} +\rho gh[/tex]
[tex]P = 1.013*10^5 +(1000)(9.8)(0.78)[/tex]
[tex]P = 108944Pa[/tex]
[tex]P = 0.1089Mpa[/tex]
Therefore the pressure inside the hose is 0.1089Mpa
