Answer:The number of mole in the compounds are:
A. 6.60 g of (NH₄)₂SO₄ contains 0.05 mole.
B. 4.5 kg Ca(OH)₂ contains 60.81 moles
The mole of a substance is related to its mass and molar mass according to the equation:
With the above formula, we can obtain the answer to the questions given above. This is illustrated below:
A. Determination of the number of mole in 6.60 g of (NH₄)₂SO₄
Molar mass of (NH₄)₂SO₄ = 2[14 + (4×1)] + 32 + (4×16)
= 2[14 + 4] + 32 + 64
= 2[18] + 32 + 64
= 36 + 32 + 64
= 132 g/mol
Mass of NH₄)₂SO₄ = 6.60 g
Mole of NH₄)₂SO₄ =?
Mole of NH₄)₂SO₄ =
Mole of NH₄)₂SO₄ = 0.05 mole
Thus, 6.60 g of (NH₄)₂SO₄ contains 0.05 mole.
B. Determination of the number of mole in 4.5 kg Ca(OH)₂
Molar mass of Ca(OH)₂ = 40 + 2(16 + 1)
= 40 + 2(17)
= 40 + 34
= 74 g/mol
Mass of Ca(OH)₂ = 4.5 kg
= 4.5 × 1000
= 4500 g
Mole of Ca(OH)₂ =?
Mole of Ca(OH)₂ =
Mole of Ca(OH)₂ = 60.81 moles
Thus, 4.5 kg Ca(OH)₂ contains 60.81 moles
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