Answer:
x equals plus or minus square root of 5 minus 1
Step-by-step explanation:
we have
[tex]x^{2} +2x=4[/tex]
Divide by 2 the coefficient of the x-term
[tex]2/2=1[/tex]
squared the number
[tex]1^2=1[/tex]
Adds both sides
[tex]x^{2} +2x+1=4+1[/tex]
[tex]x^{2} +2x+1=5[/tex]
Rewrite as perfect squares
[tex](x+1)^{2}=5[/tex]
take the square root both sides
[tex]x+1=(+/-)\sqrt{5}[/tex]
[tex]x=(+/-)\sqrt{5}-1[/tex]
therefore
x equals plus or minus square root of 5 minus 1
