takaylawilliams2 takaylawilliams2
  • 02-01-2020
  • Mathematics
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[tex](1 \times 10^{5)(6 \times {10}{4} [/tex]



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r3t40
r3t40 r3t40
  • 02-01-2020

Note that [tex]10^a\cdot10^b=10^{a+b}[/tex] or more general form, [tex]a^b\cdot a^c=a^{b+c}[/tex].

[tex]10^5\cdot6\cdot10^4=\boxed{6\cdot10^9}[/tex]

Hope this helps.

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